A complex number z can be expressed as: z = a + bi
where a and b are real numbers, and i = (-1)
A complex number can also be expressed in polar form:
z = r(cos + i sin ) = re^(i)
where r is the modulus and is the argument
(cos + i sin )^n = cos(n) + i sin(n)
Useful for finding powers and roots of complex numbers
The n-th roots of z = re^(i) are:
z_k = r^(1/n) [cos(( + 2k)/n) + i sin(( + 2k)/n)], k = 0, 1, ..., n-1
Find the square roots of z = 16e^(i(/4))
Solution: z_k = 4[cos(/8 + k) + i sin(/8 + k)], k = 0, 1
This gives two distinct roots: 4[cos(/8) + i sin(/8)] and 4[cos(9/8) + i sin(9/8)]
e^(i) = cos + i sin
Connects exponential, trigonometric, and complex functions
Distance between two points (x, y) and (x, y):
d = [(x-x) + (y-y)]
Distance from point (x, y) to line ax + by + c = 0:
d = |ax + by + c|/(a + b)
Midpoint of segment with endpoints (x, y) and (x, y):
M = ((x+x)/2, (y+y)/2)
Slope of line through (x, y) and (x, y):
m = (y-y)/(x-x)
Standard form with center (h, k) and radius r:
(x - h) + (y - k) = r
Standard form with center (h, k), semi-major axis a, and semi-minor axis b:
(x - h)/a + (y - k)/b = 1
Vertical form with vertex (h, k):
(x - h) = 4p(y - k)
Horizontal form with vertex (h, k):
(y - k) = 4p(x - h)
Horizontal form with center (h, k):
(x - h)/a - (y - k)/b = 1
Vertical form with center (h, k):
(y - k)/a - (x - h)/b = 1
Distance between points (x, y, z) and (x, y, z):
d = [(x-x) + (y-y) + (z-z)]
Sphere equation with center (h, k, l) and radius r:
(x - h) + (y - k) + (z - l) = r
Every complex number z = a + bi corresponds to a point (a, b) in the complex plane:
Find the image of point z = 3 + 2i under a 90 counterclockwise rotation about the origin.
Solution: z' = ze^(i/2) = (3 + 2i)(cos(/2) + i sin(/2)) = (3 + 2i)(0 + i1) = (3 + 2i)i = 3i + 2i = 3i - 2 = -2 + 3i
The point (3, 2) rotates to (-2, 3).
Using De Moivre's theorem to find trigonometric identities:
Find cos(3) using De Moivre's theorem.
Solution: cos(3) + i sin(3) = (cos + i sin )
= cos + 3i cos sin - 3cos sin - i sin
Therefore: cos(3) = cos - 3cos sin
A Mbius transformation is of the form:
f(z) = (az + b)/(cz + d) where ad - bc 0
These transformations map circles and lines to circles and lines in the complex plane.
