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Quantitative Aptitude Tricks

Quantitative aptitude tests are a staple of many competitive exams, online assessments, and job interviews. While a solid grasp of concepts is essential, mastering a few wellchosen shortcuts can dramatically improve accuracy and speed. This page gathers some of the most useful tricks, illustrated with clear examples, so you can tackle a wide variety of problems without getting bogged down in lengthy calculations.

1. Percentage Tricks

Percentage problems often involve finding the whole from a part, the part from a whole, or the change between two numbers. The following shortcuts cut down on mental arithmetic.

1.1. Finding the Whole Quickly

If x% of a number equals A, the whole can be obtained as A 100 / x. To avoid division, rewrite the divisor as a product of easy numbers.

25% of a number is 48.
Whole = 48 100 / 25 = 48 4 = 192.

1.2. Percent Increase/Decrease in One Step

To add 15% to a number, multiply the number by 1.15 (or add 10% and then half of that extra 5%). Similarly, a 20% reduction is the same as multiplying by 0.8.

Reduce 350 by 18%: 350 0.82 = 287.

1.3. CrossMultiplication Shortcut for 1%

One percent of any number = the number divided by 100. For fast mental work, move the decimal two places left. Use this to derive other percentages instantly.

7% of 845 1% = 8.45; 7% = 8.45 7 = 59.15.

2. Ratio & Proportion Tricks

Ratios compare quantities, and proportion problems often ask for an unknown term when three of the four values are known. The crossmultiplication habit works, but a few additional shortcuts speed things up.

2.1. Simplify Before Solving

Always reduce the ratio to its simplest form; this prevents large numbers later.

The ratio 48:180 simplifies to 8:30 4:15. If the sum of the two parts is 190, one part = 190 4 / (4+15) = 190 4 / 19 = 40.

2.2. Alligation for Mixture Problems

When mixing two solutions of different concentrations, calculate the difference between each concentration and the desired concentration. The quantities are inversely proportional to those differences.

Mix a 30% acid solution with a 70% solution to obtain 40% acid.
Differences: |3040| = 10, |7040| = 30.
Ratio of 30% to 70% = 30:10 = 3:1. Hence use three parts of 30% and one part of 70%.

3. Time & Work Tricks

Timework questions revolve around the concept of work = rate time. Treat rates as fractions of a job per day, then manipulate them algebraically.

3.1. Use 1day as Common Denominator

When two workers together finish a job in d days, each workers individual time can be found by inverting the rate.

A and B together finish a task in 6 days. A alone can finish it in 9 days. Find Bs time.
Rate of A = 1/9, combined rate = 1/6 Rate of B = 1/6 1/9 = (32)/18 = 1/18.
Hence B alone needs 18 days.

3.2. FourStep Shortcut for Multiple Workers

1 Find the least common multiple (LCM) of the individual times.
2 Convert each workers speed to units per LCM days.
3 Add the units to get total work per LCM days.
4 Divide the LCM by the total work to obtain the combined time.

Workers finish a job in 12, 20, and 30 days respectively. LCM of 12, 20, 30 = 60.
Units: 60/12 =5, 60/20 =3, 60/30 =2 total =10 units per 60 days.
Combined time = 60 /10 = 6 days.

4. Algebra Shortcuts

Algebraic manipulations can be timeconsuming if you rely on long expansions. Memorise a few patterns to cut the work dramatically.

4.1. Square of a Number Ending in 5

For any twodigit number 10a+5, its square = a(a+1) followed by 25.

75 a = 7 78 = 56 result = 5625.

4.2. Difference of Squares

Formula: (x+y)(xy) = xy. Use it to avoid expanding.

Find (10199).
= (101+99)(10199) = 2002 = 400.

4.3. Quick Factorisation of Quadratics

For ax+bx+c, when a = 1, look for two numbers whose product = c and sum = b. If a 1, use the acmethod.

Factorise 6x+11x+3.
ac = 18. Numbers that multiply to 18 and sum to 11 9 and 2.
Split middle term: 6x+9x+2x+3 = 3x(2x+3) + 1(2x+3) = (3x+1)(2x+3).

5. Probability Tricks

Probability problems can look intimidating, but a few guiding ideas keep them simple.

5.1. Complement Method

When the direct calculation is messy, compute the probability of the opposite event and subtract from 1.

A bag contains 4 red, 5 blue, and 6 green balls. Find the probability of drawing a ball that is not blue.
Total =15; P(blue) =5/15 =1/3.
Desired probability = 11/3 = 2/3.

5.2. Division into Cases Shortcut

When events are mutually exclusive, add their individual probabilities. When independent, multiply.

Toss a fair coin twice. Probability of getting at least one head = 1P(no head) = 1(1/2) = 3/4.

5.3. Use Symmetry

If a problem is symmetric, the probability of each symmetric outcome is the same. This reduces counting effort.

Three identical balls are placed into two distinct boxes. What is the probability that each box contains at least one ball?
Total distributions = 2=8. Favorable cases = {21, 12} 2 ways.
Probability = 2/8 = 1/4.

Conclusion

Even the most challenging quantitative aptitude questions become approachable when you keep a toolbox of reliable shortcuts. The key is practice: try each trick on a variety of sample problems until it feels instinctive. Over time youll notice a marked improvement in both speed and confidence, turning exams that once seemed daunting into opportunities to showcase your analytical agility.

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